Termination w.r.t. Q of the following Term Rewriting System could not be shown:

Q restricted rewrite system:
The TRS R consists of the following rules:

c(c(c(b(x)))) → a(1, b(c(x)))
b(c(b(c(x)))) → a(0, a(1, x))
a(0, x) → c(c(x))
a(1, x) → c(b(x))

Q is empty.


QTRS
  ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

c(c(c(b(x)))) → a(1, b(c(x)))
b(c(b(c(x)))) → a(0, a(1, x))
a(0, x) → c(c(x))
a(1, x) → c(b(x))

Q is empty.

Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:

C(c(c(b(x)))) → C(x)
A(1, x) → C(b(x))
B(c(b(c(x)))) → A(1, x)
A(1, x) → B(x)
C(c(c(b(x)))) → A(1, b(c(x)))
B(c(b(c(x)))) → A(0, a(1, x))
A(0, x) → C(x)
A(0, x) → C(c(x))
C(c(c(b(x)))) → B(c(x))

The TRS R consists of the following rules:

c(c(c(b(x)))) → a(1, b(c(x)))
b(c(b(c(x)))) → a(0, a(1, x))
a(0, x) → c(c(x))
a(1, x) → c(b(x))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ DependencyPairsProof
QDP
      ↳ EdgeDeletionProof

Q DP problem:
The TRS P consists of the following rules:

C(c(c(b(x)))) → C(x)
A(1, x) → C(b(x))
B(c(b(c(x)))) → A(1, x)
A(1, x) → B(x)
C(c(c(b(x)))) → A(1, b(c(x)))
B(c(b(c(x)))) → A(0, a(1, x))
A(0, x) → C(x)
A(0, x) → C(c(x))
C(c(c(b(x)))) → B(c(x))

The TRS R consists of the following rules:

c(c(c(b(x)))) → a(1, b(c(x)))
b(c(b(c(x)))) → a(0, a(1, x))
a(0, x) → c(c(x))
a(1, x) → c(b(x))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
We deleted some edges using various graph approximations

↳ QTRS
  ↳ DependencyPairsProof
    ↳ QDP
      ↳ EdgeDeletionProof
QDP

Q DP problem:
The TRS P consists of the following rules:

C(c(c(b(x)))) → C(x)
A(1, x) → C(b(x))
B(c(b(c(x)))) → A(1, x)
A(1, x) → B(x)
C(c(c(b(x)))) → A(1, b(c(x)))
B(c(b(c(x)))) → A(0, a(1, x))
A(0, x) → C(x)
C(c(c(b(x)))) → B(c(x))
A(0, x) → C(c(x))

The TRS R consists of the following rules:

c(c(c(b(x)))) → a(1, b(c(x)))
b(c(b(c(x)))) → a(0, a(1, x))
a(0, x) → c(c(x))
a(1, x) → c(b(x))

Q is empty.
We have to consider all minimal (P,Q,R)-chains.